JEE MAIN - Physics (2022 - 28th June Morning Shift - No. 26)
A singly ionized magnesium atom (A = 24) ion is accelerated to kinetic energy 5 keV, and is projected perpendicularly into a magnetic field B of the magnitude 0.5 T. The radius of path formed will be _____________ cm.
คำตอบ
10
คำอธิบาย
$$R = {{mv} \over {qB}}$$
$$R = {{\sqrt {2mKE} } \over {qB}}$$
$$ = {{\sqrt {2 \times 24 \times 1.67 \times {{10}^{ - 27}} \times 5 \times 1.6 \times {{10}^{ - 16}}} } \over {1.6 \times {{10}^{ - 19}} \times 0.5}}$$
= 10.009 cm = 10 cm